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x^2-x-3906=0
We add all the numbers together, and all the variables
x^2-1x-3906=0
a = 1; b = -1; c = -3906;
Δ = b2-4ac
Δ = -12-4·1·(-3906)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15625}=125$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-125}{2*1}=\frac{-124}{2} =-62 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+125}{2*1}=\frac{126}{2} =63 $
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